300-20m=m^2

Solution for 300-20m=m^2 equation:

300-20m=m^2

We move all terms to the left:

300-20m-(m^2)=0

determiningTheFunctionDomain
-m^2-20m+300=0

We add all the numbers together, and all the variables

-1m^2-20m+300=0

a = -1; b = -20; c = +300;
Δ = b2-4ac
Δ = -202-4·(-1)·300
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*-1}=\frac{-20}{-2}
=+10
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*-1}=\frac{60}{-2}
=-30
$